Understanding power factor is easy when you relate it to beer!

[veracon0700]

Here is a classic analogy using beer that will help you to better understand power factor...

Imagine you have a freshly poured mug of your favorite brew sitting in front of you.

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The drinkable portion of your beer is represented by Real Power (expressed in kW). Real Power may also be called Actual Power, Active Power or Working Power. This is what actually powers electrical equipment and performs useful work (in this case, quenching your thirst).

Along with your brew comes a little bit of foam, and that foam just isn't going to do anything useful, so consider this undrinkable portion of your beer to be Reactive Power, represented by KVAR. This is the power that magnetic equipment like transformers, motors and relays need to produce their magnetizing flux. Think of the foam as a reaction from pouring the beer.

The combination of drinkable beer (kW) and foam (kVAR) inside of your mug represents the Apparent Power, or KVA.

Power Factor is simply the ratio of Real Power (kW) to Apparent Power (kVA) and is represented by the following formula: PF = KW / KVA.

Using our beer analogy you could write the formula like this: PF = Beer / Drinkable Beer + Foam.

For any given KVA,the more foam you have (the higher the percentage of KVAR), the lower your ratio of KW (beer) to KVA (drinkable beer + foam). Thus, the lower your power factor.

The less foam you have (the lower the percentage of KVAR), the higher the ratio of KW (drinkable beer) to KVA (drinkable beer plus foam). As your foam (or KVAR) approaches zero, the power factor approaches 1.

[Scubasteve523]

Very helpful!!!

[randywright]

this concept is best understood with a live demonstration. :p cheers!

[TheBreakerGuy]

Ha! That is very helpful.

[deespino]

i think you might have meant to say PF is the ratio of real power (kW) to apparent power (KVA)

[veracon0700]

D'oh! Thanks for pointing that out desspino, I will make the change. :cool:


i think you might have meant to say PF is the ratio of real power (kW) to apparent power (KVA)

[MDTannen]

Next time I'm talking shop with my Uncle, who did that for Edison in his early days, I'll ask him if it was because utilities don't like too much foam. I may get a weird look, but if he says yes, he gets a high five!
Classic analogy, good post.

[cj65shelby]

I love this explanation.....See learning can beer fun !!!

[adamcarter]

This is the best analogy I have seen. Thanks!

[IncredibleGreg]

this concept is best understood with a live demonstration. :p cheers!

I'll drink to that!

[Ronwilson1801]

Here is a classic analogy using beer that will help you to better understand power factor...

Imagine you have a freshly poured mug of your favorite brew sitting in front of you.

75

The drinkable portion of your beer is represented by Real Power (expressed in kW). Real Power may also be called Actual Power, Active Power or Working Power. This is what actually powers electrical equipment and performs useful work (in this case, quenching your thirst).

Along with your brew comes a little bit of foam, and that foam just isn't going to do anything useful, so consider this undrinkable portion of your beer to be Reactive Power, represented by KVAR. This is the power that magnetic equipment like transformers, motors and relays need to produce their magnetizing flux. Think of the foam as a reaction from pouring the beer.

The combination of drinkable beer (kW) and foam (kVAR) inside of your mug represents the Apparent Power, or KVA.

Power Factor is simply the ratio of Real Power (kW) to Apparent Power (kVA) and is represented by the following formula: PF = KW / KVA.

Using our beer analogy you could write the formula like this: PF = Beer / Drinkable Beer + Foam.

For any given KVA,the more foam you have (the higher the percentage of KVAR), the lower your ratio of KW (beer) to KVA (drinkable beer + foam). Thus, the lower your power factor.

The less foam you have (the lower the percentage of KVAR), the higher the ratio of KW (drinkable beer) to KVA (drinkable beer plus foam). As your foam (or KVAR) approaches zero, the power factor approaches 1.

Incase anyone wants to see the Power Triangle


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[harrw626]

This is a lot better than the power triangle they teach in school. This is a very straightforward example. I'm going to remember and use this.

[Raj5454]

Here is a classic analogy using beer that will help you to better understand power factor...

Imagine you have a freshly poured mug of your favorite brew sitting in front of you.

75

The drinkable portion of your beer is represented by Real Power (expressed in kW). Real Power may also be called Actual Power, Active Power or Working Power. This is what actually powers electrical equipment and performs useful work (in this case, quenching your thirst).

Along with your brew comes a little bit of foam, and that foam just isn't going to do anything useful, so consider this undrinkable portion of your beer to be Reactive Power, represented by KVAR. This is the power that magnetic equipment like transformers, motors and relays need to produce their magnetizing flux. Think of the foam as a reaction from pouring the beer.

The combination of drinkable beer (kW) and foam (kVAR) inside of your mug represents the Apparent Power, or KVA.

Power Factor is simply the ratio of Real Power (kW) to Apparent Power (kVA) and is represented by the following formula: PF = KW / KVA.

Using our beer analogy you could write the formula like this: PF = Beer / Drinkable Beer + Foam.

For any given KVA,the more foam you have (the higher the percentage of KVAR), the lower your ratio of KW (beer) to KVA (drinkable beer + foam). Thus, the lower your power factor.

The less foam you have (the lower the percentage of KVAR), the higher the ratio of KW (drinkable beer) to KVA (drinkable beer plus foam). As your foam (or KVAR) approaches zero, the power factor approaches 1.

[Raj5454]

Power Factor = kVA/kW = (kW + kVAR)/kW

Lesser the kVar, the better the power factor

But we can not reduce the kVAr of the electrical machine.

[Kalbi_Rob]

Power Factor = kVA/kW = (kW + kVAR)/kW

Lesser the kVar, the better the power factor

But we can not reduce the kVAr of the electrical machine.

Yes you can. First is through engineering and redesigning of the machine with power factor correction built in, but this is costly and has to be built into the machine before use. Secondly, if you work in substations, you know we can power factor correct with the use of capacitor banks and reactors.
KVAR is only produced through reactive (imaginary) components such as capacitance and inductance. Since capacitance is inversely proportional to inductance, we can use the opposite component to counteract the other.

[Izeldeen]

Very helpful!!!

hahahaha