View Full Version : A 5 H inductor is subjected to an electric current that changes at a rate of 4.5 amps
cnowak
September 13, 2021, 01:37 PM
A 5 H inductor is subjected to an electric current that changes at a rate of 4.5 amps per second. How much voltage will be dropped by the inductor?
11.25
22.50
37.50
45.00
Kalbi_Rob
September 14, 2021, 06:46 AM
A 5 H inductor is subjected to an electric current that changes at a rate of 4.5 amps per second. How much voltage will be dropped by the inductor?
11.25
22.50
37.50
45.00
V = L (di/dt) or L*((I1-I0)/(t1-t0))
V = 5H ((4.5A-0)/(1s-0s)) = 5H*(4.5A/1s) = 5H*4.5(A/s) = 22.5 V
briantilley123
September 16, 2021, 05:18 AM
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Izeldeen
November 7, 2021, 08:16 PM
V = L (di/dt) or L*((I1-I0)/(t1-t0))
V = 5H ((4.5A-0)/(1s-0s)) = 5H*(4.5A/1s) = 5H*4.5(A/s) = 22.5 V
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