What KVAR is needed to get at PF of .95?

[cbrazzil]

Given 750KVA and a PF of .75, what KVAR is needed to get at PF of .95?

Unknowns= KW and KVAR1 and KVAR2
First solve for Ø
PF=COSØ Ø=41.4
Next solve for W
COSØ=W/VA 750,000*COS(41.4)=562500 Watts or 562.5KW
We don't need to solve for the KVAR1

New system of PF of .95
Solve for Ø=18.2
Next solve for VAR
TANØ=VAR/W 562500*TAN(18.2)= 184940.59 185=KVAR is the needed KVAR