Can this CT produce enough voltage to trip a relay?

[Dublin]

You do have to consider the C20. That is the maximum voltage that the CT is able to produce. The circuit requires 25V in order to operate. Thus this CT will not work as a relaying CT. However, it will work as a metering CT because the total circuit burden is .25 which is less than the .9 burden rating the CT has.

I attached a link to a great powerpoint that has this exact question in it.

https://nanopdf.com/queue/instrument...E1MC4yNDAuMjE3

Hope this helps

How do you know that it requires 25V in order to operate the circuit?

This would most likely be able to operate the relay. Most protection is set far below the 20xIn rule of thumb if the question was "Is this CT correctly sized to be used as a protection CT?" I would agree that it is not, but the question was would this operate the protection, and there is not enough information to answer that,

In all likelihood, it would operate the protection unless the protection is exclusively very high current trips such as an instantaneous trip.

To know if this would operate the relay, we would need to know the protection setpoints of the relay.