A wye-delta transformer has a turns ratio of 2:1. It has a secondary line voltage of 480 V. The secondary is connected to a wye-connected three-phase resistive load of 50 ohms in each phase. How much is the secondary line current?

My answer is 9.6 Amps, I used 480V since it wont matter in the delta side (V line = V phase) and divide 50 ohms from it resulting 9.6 amps, however I got the question wrong. I know I line = 1.73 * I phase. I cant remember how to solve for it.